Question

two trains move in the same direction at 50 kmph and 32 kmph respectively. a man in the slower trainobserves the 15 seconds elapse before the faster train completely passes by him.what is the length of faster train

Answer 1

Two traines relative speed=50-32=18km/hr kilometer per hour is converted into meter per second 18*5/18=5meter/sec given time =15sec totel length=5*15=75meters it is the correct answer 

Answer 2

Answer:

The length of faster train is 75 m.

Explanation:

Given that,

Two trains move in the same direction at 50 km/h and 32 km/h respectively.

The relative speed is defined as,

$v_{fs}=v_{f}-v_{s}$

Where, $v_{f}$=speed of faster train

$v_{s}$=speed of slower train

Put the value into the formula

$v_{fs}=50-32$

$v_{fs}=18\ km/h$

Using formula of distance

The distance is the product of the speed and time.

$D = v\times t$

$D = 18\times\dfrac{5}{18}\times15$

$D = 75\ m$

Hence, The length of faster train is 75 m.