Question

Two trains of equal length are running
on parallel lines in the same direction at
the rate of 64 Km/hr and 44 Km/hr. The
faster train passes the slower train in
48 seconds. The length of each train is
(A) 1440 m (B) 750 m
690 m
(D) 720 m
(C)

Answer 1

Answer:

The length of each of the train will be 720 m.

Step-by-step explanation:

As per the data given in the question,

We have to determine the length of the train.

As per question,

It is given that,

Two trains of equal length are running on parallel lines in the same direction.

The speed of the trains is 64 Km/hr and 44 Km/hr.

The faster train passes the slower train in 48 seconds.

As we know that,

As per Speed, Distance and Time concept, the value of the distance can be determined by using the formula $Speed =\frac{Distance}{Time} \Rightarrow Distance = Speed \times Time$

Let us assume that the length of both the trains are L1 and L2.

We know,

When two trains are running in same direction, the time can be determined by using the formula:

$Time =\frac{l_1+L_2}{S_1+S_2}$

Where, L1 is the length of faster train, and S1 is the speed of faster train, while L2 is the length of the slower train and S2 is the speed of slower train.

As here length of both trains are equal.

So, we can write the above formula as:

$Time =\frac{l_1+L_1}{S_1+S_2}=\frac{2l_1}{S_1+S_2}$

As speed are given in Kmph and time in sec. so we will convert Kmph into mps.

So, the value of S1 and S2 will be = 64+44 = 108 Kmph.

So, the value of speed in mps will be $108 \times \frac{5}{18}=30\:mps$

So, putting the value in above equation,

We will get,

$48=\frac{2L_1}{30}\\\Rightarrow 2L_1=30 \times 48\\\Rightarrow L_1=15 \times 48=720\:m$

So, the length of each of the train will be 720 m.

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