Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
Answers
Answered by
6
Speed of the first train =
120/10 = 12m/sec
Speed of the second train = 120/15 = 8m/sec
=> Relative speed = (12 + 8) = 20 m/sec
=> Required time = (120+120)/20 = 12 sec
Hence,the trains will cross each other in 12 secs.
Speed of the second train = 120/15 = 8m/sec
=> Relative speed = (12 + 8) = 20 m/sec
=> Required time = (120+120)/20 = 12 sec
Hence,the trains will cross each other in 12 secs.
Similar questions