Question

Two trains P and Q of length 300 m and 500 m are moving on two parallel tracks each with a uniform speed of 72 km/h in the same direction, with Q ahead of P. The driver of train P decide to overtake train Q and accelerates by 2.0 m/s², if after 40 s the guard of P just brushes past the driver of Q, then the original distance between the trains​

Answer 1

Answer ---

Train A:-

Speed = 72km/h = 72×5/18 = 20 m/s

Time = 50 seconds

Distance = Speed × Time

= 20 × 50

= 1000 m

Train B:-

u = 72 km/h = 20 m/s

t = 50 seconds

a = 1 m/s²

s = ut + 1/2at²

= 20×50 + 1/2×1×(50)²

= 1000+ 1/2×2500

= 1000+1250

= 2250 m

Distance travelled more by train B = 2250-1000

= 1250 m

Length of 1 train = 400 m

Distance between them = 1250-400

= 850 m

Hope it helps you

Answer 2

Here you go.. Good luck for boards!