Two trains running at the rate of 75km and 60km an hour respectively on parallel
they are running in the same direction at the same rates as before, a person sitting in
the faster train observes that he passes the other in 33.5 seconds. Find the lengths of
the trains.
Answers
Step-by-step explanation:
) length 1 =168.75 m, length 2 =131.25 m
sum of length of two trains = 135*8*5/18 = 300mtr
length of slower train = 15*(5/18)*(63/2) = 131.25 mtr
lenth of other train = 300-131.25= 168.75 mtrs
Answer:
The length of the slower train is 1395.5 meters,
and the length of the faster train is 1449.5 meters.
Step-by-step explanation:
As per the given data, Let's assume the length of the slower train is “L” meters. Then, the length of the faster train is “L + x" meters, where x is the difference in their lengths.
In 33.5 seconds, the faster train covers a distance of (75 x 33.5/3600) km = 0.0291 km = 291 m.
At the same time, the slower train covers a distance of (60 x 33.5/3600) km = 0.0237 km = 237 m.
Since the person in the faster train sees the whole slower train pass by, the length of the slower train "L" is equal to the difference in their speeds in meters/second multiplied by the time in seconds:
L = (75 - 60) x (33.5/3600) x 1000 = 150 x 0.00931 x 1000 = 1395.5 m
Finally, the difference in length x = 291 - 237 = 54 m
So, the length of the faster train is L + x = 1395.5 + 54 = 1449.5 m
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