Two trains running in opposite directions cross a man standing on the
platform in 27 seconds and 17 seconds respectively and they cross each
other in 23 seconds. The ratio of their speeds is
karneet:
the ratio of the speed is? we need to find that out?
can you please make the question more clear...
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Let the lengths of the trains be x, y.
Then the velocities of the trains are x/27, y/17.
When they cross each other each one has to cover the other train's length and its own length hence the relative velocity is (x+y)/23=x/27+y/17.
Solving this you get x/y=81/34
can you please explain how you could relate the relative velocity to the sum of individual velocities
Relative velocity is the sum of individual velocities when the objects move in opposite directions
In this case since any one of the trains has to travel a total distance of x+y in 23 seconds it's (x+y)/23
woah. ur absolutely rite :O
Yup got it.. thanx..
no this is not the correct answer
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x + 17y/ x+ y = 23
27x + 17y = 23x + 23y
4x = 6y
x = 3 .
y = 2
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x + 17y/ x+ y = 23
27x + 17y = 23x + 23y
4x = 6y
x = 3 .
y = 2
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