two trains start from P and Q respectively and travel towards each other at a speed of 50 km per hour and 40 km per hour respectively by the time they meet the first train travelled 100km more than the second the distance between P and Q is what
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let distance be x
time in which they will meet =x/90
distance travelled by first train in x/90 hrs=50×{x/90)----------------i
distance travelled by second train in same time=40×{x/90)----------ii
difference in distance is given 100km
subtract ii from i and equate it to 100
taking x/90 common
x/90(50-40)=100
10x=9000
x=900km
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