Two trains start simultaneously from two station 300 km apart and move towards each other. The speed of one train is more than the other by 20 km/hr. If the distance between the trains after two hours is 20 km, find the speeds of the trains.
Answers
Answer:
Let the trains start from station A and station B respectively.
Let the first train start from station A and the second train start from station B at the same time and move towards each other.
Let the speed of the first train be x km/hr
∴ the speed of the second train =(x+20) km/hr
Distance travelled by first train in 2 hours =2x km
Distance travelled by second train in 2 hours =2(x+20) km =(2x+40) km
Given, distance between two stations =300 km
According to the given condition, we have
Distance travelled by first train + Distance travelled by second train +20=300
i.e., 2x+(2x+40)+20=300
4x+60=300
4x=300−60 ....[Transposing 60 to RHS]
4x=240
Thus, x=
4
240
=60
∴ Speed of the first train =60 km/hr and
speed of the second train =(60+20/h
Answer :
Let the speed of the first train be x km/hr so, the speed of other train = ( x + 20 )
Distance travelled by first train in 1 hr = x km
Distance travelled by first train in 2 hrs = ( 2x ) km
Distance travelled by other train in 1 hr = ( x + 20 ) km
Distance travelled by other train in 2 hrs = 2( x+20 )km
= ( 2x + 40 ) km
The distance between two stations is given as 300 km .
ATQ,
Distance travelled by first train + Distance travelled by other train + 20 = 300
i.e. 2x + ( 2x + 40 ) + 20 = 300
2x + 2x + 40 + 20 = 300
4x + 60 = 300
4x = 300 - 60
4x = 240
Thus, x = 240/4 = 60
Therefore, Speed of the first train = 60km/hr
Speed of the other train = (60 +20)km/hr
= 80km/hr