Two trains start simultaneously in opposite direction from two stations a and B which are 40 km apart. The speed of one train is 5 km/h greater than the other after two hours .After 2 hour,if the distance between two trains is 90 km find the speed of the faster train.(answer is 80 km/hr , how)
Answers
Answer:
Let the trains start from station A and station B respectively.
Let the first train start from station A and the second train start from station B at the same time and move towards each other.
Let the speed of the first train be x km/hr
∴ the speed of the second train =(x+20) km/hr
Distance travelled by first train in 2 hours =2x km
Distance travelled by second train in 2 hours =2(x+20) km =(2x+40) km
Given, distance between two stations =300 km
According to the given condition, we have
Distance travelled by first train + Distance travelled by second train +20=300
i.e., 2x+(2x+40)+20=300
4x+60=300
4x=300−60 ....[Transposing 60 to RHS]
4x=240
Thus, x=
4
240
=60
∴ Speed of the first train =60 km/hr and
speed of the second train =(60+20) krn/h =80 km/hr.
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