two trains start simultaneously in opposite directions from two stations A and B which are 400km apart.the speed of one of the trains is 5km/h greater than the other.After 2 hours,if the distance between the two trains is 90km,find the speed of the faster train.
STEP BY STEP EXPLANATION
Answers
Answer:
Let speed of one train is = x
then speed of other train will be = x+5
if the distance between them after 2 hours is 90 km then they had travelled 310 kms in total
since distance = speed x time
310 = [speed of first train x 2] + [speed of second train x 2]
310 = [x*2] + [x+5*2]
310 = 2x + 2x +10
310 = 4x + 10
310 - 10 = 4x
300 = 4x
300/4 = x
75 = x
therefore speed of first train is 75 and second train is 80
Answer:
Bro correct answer is 80km per hour
Step-by-step explanation:
Let speed of one train is = x
then speed of other train will be = x+5
if the distance between them after 2 hours is 90 km then they had travelled 310 kms in total
since distance = speed x time
310 = [speed of first train x 2] + [speed of second train x 2]
310 = [x*2] + [x+5*2]
310 = 2x + 2x +10
310 = 4x + 10
310 - 10 = 4x
300 = 4x
300/4 = x
75 = x
therefore speed of first train is 75 and second train is 80
This is only the correct answer.... ☝️