Two trains starting at same time, one from bangalore to mysore and other in opposite direction arrive at their destination 1 hr and 4 hours respectively after passing each other. how nuch faster is one train from other?
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let distance between the 2 cities = d.
let u and v be their respective speed.
and finally t is the time passed (in hour) since their departure until they surechigatta in their journey.
u = d/(t+1) and v = d/(t+4)
then u > v.
u - v
= [ d/(t+1) ] - [ d/(t+4) ]
= d [(t+4) - (t+1) ] / (t+1)(t+4)
= 3d / (t+1)(t+4)
d = t * [ d/(t+1) + d/(t+4) ]
1 = t (2t+5) / (t+1)(t+4)
(t+1)(t+4) = t (2t+5)
t^2 + 5t + 4 = 2t^2 + 5t
t^2 = 4
t = +-2
t > 0 no de, t = 2
d = u (t+1) = v (t+4)
d = 3u = 6v
u = 2v
one train is twice as fast as the other train.
let u and v be their respective speed.
and finally t is the time passed (in hour) since their departure until they surechigatta in their journey.
u = d/(t+1) and v = d/(t+4)
then u > v.
u - v
= [ d/(t+1) ] - [ d/(t+4) ]
= d [(t+4) - (t+1) ] / (t+1)(t+4)
= 3d / (t+1)(t+4)
d = t * [ d/(t+1) + d/(t+4) ]
1 = t (2t+5) / (t+1)(t+4)
(t+1)(t+4) = t (2t+5)
t^2 + 5t + 4 = 2t^2 + 5t
t^2 = 4
t = +-2
t > 0 no de, t = 2
d = u (t+1) = v (t+4)
d = 3u = 6v
u = 2v
one train is twice as fast as the other train.
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