Question

Two trains starts simultaneously from points a and b which are 400 apart the speed of one of train is 5km greater than the other after 2 if the dis b/w the two trains is 90 km find the speed of each train

Answer 1

let speed of one train is = x
then speed of other train will be = x+5
if the distance between them after 2 hours is 90 km then they had travelled 310 kms in total

since distance = speed x time
 
310 = [speed of first train x 2] + [speed of second train x 2]
310 = [x*2] + [x+5*2]
310 = 2x + 2x +10
310 = 4x + 10
310 - 10 = 4x
300 = 4x
300/4 = x
75 = x

therefore speed of first train is 75 and second train is 80

Answer 2

Answer:80km per hour

Step-by-step explanation:

Let speed of one train is = x

then speed of other train will be = x+5

if the distance between them after 2 hours is 90 km then they had travelled 310 kms in total

since distance = speed x time

310 = [speed of first train x 2] + [speed of second train x 2]

310 = [x*2] + [x+5*2]

310 = 2x + 2x +10

310 = 4x + 10

310 - 10 = 4x

300 = 4x

300/4 = x

75 = x

therefore speed of first train is 75 and second train is 80