Question

Two trains T1 and T2 start simultaneously from two stations X and Y respectively towards each other. If they are 70 km apart both 3 and 6 hours after start, then find the distance between the two stations.

Answer 1

Answer:

366m

because train a start with more speed and train b has less speed

Answer 2

Answer:

210 km.

Step-by-step explanation:

Let the speed of the two trains T1 and T2 are u km/hour and v km/hour respectively.

Again assume that the distance between the stations X and Y is d km.

As the trains T1 and T2 started simultaneously to move towards each other from station X and station Y respectively, and after 3 hours and after 6 hours they were 70 km apart, then we can write the following equations ,

(u+v)3=d-70  .....(1)

and, (u+v)6 =d+70 ...... (2)

Now, dividing equation (2) with equation(1), we get,

(d+70)/(d-70) =6/3

⇒ d+70 =2d- 140

⇒ d= 210.

Hence, the distance between the two stations X and Y will be 210 km. (Answer)