Two trains X and Y start from a railway station at the same time.The X train travels due west and the Y train due north. the X train travels 5km/hr faster that the Y train.If after two hours , they are 50 km apart, find the average speed of two trains.
Answers
Answer:
17.5 km/Hr
Step-by-step explanation:
Two trains X and Y start from a railway station at the same time.The X train travels due west and the Y train due north. the X train travels 5km/hr faster that the Y train.If after two hours , they are 50 km apart, find the average speed of two trains.
Let say speed of Y train = Y km/Hr
X train travels 5km/hr faster that the Y train
Speed of X train = Y + 5 km/Hr
Distance traveled by X Train in 2hrs = 2(Y + 5) km West
Distance traveled by Y Train in 2hrs = 2Y km North
North & West are perpendicular to each other
Distance between train² = North Distance² + West Distance²
=> 50² = (2Y)² + (2(Y+5))²
=> 25² = Y² + (Y+5)²
=> 625 = Y² + Y² + 25 + 10Y
=> 2Y² + 10Y - 600 = 0
=> Y² + 5Y - 300 = 0
=> Y² + 20Y - 15Y -300 = 0
=> Y(Y +20) -15(Y +20) = 0
=> (Y -15) (Y +20) = 0
Y = 15
Speed of Y Train = 15 km/Hr
Speed of X train = 20 km/Hr
Average speed of both Train = (15 + 20)/2 = 17.5 km/Hr
Speed of first train is 20 Km/h and speed of 2nd train is 15 Km/h
➣ Let the 2nd train travel at X km/h
➣Then, the speed of a train is (5 +x) Km/hour.
➣ let the two trains live from station M.
➣ Distance travelled by first train in 2 hours
= MA = 2(x+5) Km.
➣ Distance travelled by second train in 2 hours
= MB = 2x Km
AB²= MB²+MA²
⟹ 50²=(2(x+5)²+(2x)²
⟹ 2500 = (2x+10)² + 4x²
⟹8x² + 40x - 2400 = 0
⟹x² + 5x - 300 = 0
⟹x² + 20x -15x - 300 = 0
⟹x(x + 20) - 15(x + 20) = 0
⟹ (x + 20)(x -15) = 0
Taking x = 15 , the speed of second train is 15 Km/h and speed of first train is 20 Km/h