Two transistors together cost 480 they are sold at profit 19% other at a loss of 15% if the selling price are equal find at the cost of lower priceed one
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Let the cost price of the lower priced one be x.
The cost of the other one will be :
480 - x
Their selling prices :
0.85x — lower priced one
And
1.19(400 - x) = 476 - 1.19x
These two selling prices are equal.
0.85x = 476 - 1.19x
0.85x + 1.19x = 476
2.04x = 476
x = 476/2.04
X = 233.33
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