Question

Two transparent elevator cars A and B are

moving in front of each other. Car A is moving

up and retarding at a1, while car B is moving

down and retarding at a2. Person in car A drops

a coin inside the car. What is the acceleration

observed by person in car B.

(1) g + a2 downward

(2) g – a1 – a2 downward

(3) g – a1 + a2 downward

(4) g + a1 – a2 downward ​

Answer 1

The acceleration as observed by person in car B is g+a2 downward

Therefore, option (1) is correct.

Step-by-step explanation:

Given

Car A is moving up but retarding at $a_1$

Car B is moving down but retarding at $a_2$

When the coin is dropped inside the elevator car A, it becomes the case of free fall

Thus, the coin falls with acceleration $g$

Acceleration of coin C w.r.t. ground

$a_{C/G}=g$

Acceleration of car B w.r.t. ground

$a_{B/G}=-a_2$

Therefore,

acceleration of coin w.r.t. car B

$a_{C/B}=a_{C/G}+a_{G/B}$

$\implies a_{C/B}=g+a_2$

The acceleration will be in downward direction

Hope this answer is helpful.

Know More:

Q: The elevator is descending with an acceleration of 2ms^-2. The mass of the block A = 0.5kg. The force exerted by the block A on block B is:

Click Here: https://brainly.in/question/7936765

Q: A stone is released from an elevator going up with an acceleration a. The acceleration of the stone after the release is:

Click Here: https://brainly.in/question/26093