Two trees 30m and 18m stand upright in a ground. If their bases 5m apart, then the distance between there top is
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0
Answer:
I think this is the correct answer just a guess
Step-by-step explanation:
Let AB=7m and CD=4m
AC=DE=4m
Now, in triangle BED is right-angled triangle.
⟹(BD)
2
=(BE)
2
+(DE)
2
⟹(BD)
2
=3
2
+4
2
⟹(BD)
2
=25
⟹(BD)
2
=5
Threfore, the distance the tops of trees in 5 meter.
Answered by
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Answer:
The answer and the steps are given above
Hope it helps you
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