Question

Two trees 7 m and 4 m high stand upright on a ground. If their bases (roots) are 4 m apart, then the distance between their tops is?

please give correct answers I saw everyone has different answers options r 3,5,4,11

please give now hurry!!!​

Answer 1

Answer:

Correct option is

B

5m

Let AB=7m and CD=4m

AC=DE=4m

Now, in triangle BED is right-angled triangle.

⟹(BD)

2

=(BE)

2

+(DE)

2

⟹(BD)

2

=3

2

+4

2

⟹(BD)

2

=25

⟹(BD)

2

=5

Threfore, the distance the tops of trees in 5 meter.

Answer 2

Answer:

QR2 = QE2 + ER2

QR2 = 32 + 42

QR2 = 9 + 6

QR2 = 25

QR = square root 25

QR = 5

Therefore, the distance between the top of the two trees is 5m