Science, asked by chakrobortyshubhanka, 11 months ago

two trees are at distance 3.14 m from each other what would be the maximum distance of an observer from tree to see them separately?

pls give me the sol ​

Answers

Answered by nihiradas18
25

Answer:

Explanation:

please see the atachment in order to understand the solve

Attachments:
Answered by Fatimakincsem
8

The  maximum distance of an observer from tree is 1.813 m

Explanation:

We are given that:

T1T2 = 3.14 m

=> T1M = MT2 = 1.57 m

Tan (Θ / 2) = T1 M / M V = (1.57 / x)

Tan (Θ / 2)  = (1.57 / x)

Now the viewer will lose vision if

tan (60°) < 1.57 / x

=> √ 3 < 1.57 / x

x = 1.57 / 3 m

VT1 = V T2 = √ (1.57 / √ 3 )^2 + ( 1.57)^2 m

VT1 = V T2  = 1.57 x 2 /  √ 3

VT1 = V T2  = 1.57 x 2 / 1.732

VT1 = V T2  = 1.813 m

Thus the  maximum distance of an observer from tree is 1.813 m

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