two trees are at distance 3.14 m from each other what would be the maximum distance of an observer from tree to see them separately?
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Explanation:
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The maximum distance of an observer from tree is 1.813 m
Explanation:
We are given that:
T1T2 = 3.14 m
=> T1M = MT2 = 1.57 m
Tan (Θ / 2) = T1 M / M V = (1.57 / x)
Tan (Θ / 2) = (1.57 / x)
Now the viewer will lose vision if
tan (60°) < 1.57 / x
=> √ 3 < 1.57 / x
x = 1.57 / 3 m
VT1 = V T2 = √ (1.57 / √ 3 )^2 + ( 1.57)^2 m
VT1 = V T2 = 1.57 x 2 / √ 3
VT1 = V T2 = 1.57 x 2 / 1.732
VT1 = V T2 = 1.813 m
Thus the maximum distance of an observer from tree is 1.813 m
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