Question

Two trees of heights 58m and 10 m stand upright on the ground, with a distance of 14 m between them.
the length of the rope stretched from the top of one tree to the top of the other tree.​

Answer 1

length of the rope is 50

Step-by-step explanation:

length of the first tree =10m

length of the second tree=58m

58-10=48

distance between them is 14m

(√48)²+(√14) ²= √x

√2304+√196=√x

x=√2500

x=50

so, length of the rope is 50.

Answer 2

The length of the rope stretched from top of one tree to the top of other tree is 50 m

Step-by-step explanation:

Two trees of heights 58 m and 10 m stand upright on the ground, with a distance of 14 m between them.

Let distance between top of the tree be d m

Please see attachment for figure.

Draw a line parallel to base from lower height of tree.

So, CD || AB

ABCD is a rectangle.

AD = BC = 10 m

DC = AB = 14 m

ED = AE - AD

     = 58 - 10

     = 48 m

In ΔDEC, ∠EDC = 90°    (Using Pythagorean theorem)

$EC^2=DE^2+DC^2$

$d^2=48^2+14^2$

$d^2=2500$

Taking square root both sides

$d=\sqrt{2500}$

$d=50$

Hence, the distance between top of the tree is 50 m

#Learn more:

application of trigonometry

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