Two triagles ABC and DEF are such that angle A of triangle ABC and angle D of triagles DEF are equal and also the opposite sides of both the angles A and D in both the triangles are equal. Prove that triangles ABC and DEF are similar?
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Answer:
Hope it helps.....
Step-by-step explanation:
In ∆ ABC and ∆ DEF :
<A = <D (Given)
<C = <F (Corresponding angles)
BC = EF (Given)
Therefore,
By AAS,
∆ ABC ≈ ∆ DEF
Hence, proven..
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