Question

two triangle ABC and DBC do have common base BC suppose a b is equal to DC and angle abc and BCD prove that AC is equal to BD​

Answer 1

Answer:

Step-by-step explanation:

in ΔABC and ΔDBC

∠ABC=∠BCD

AB = DC

BC = CB

BY SAS CRITERIA

ΔABC≅ΔDBC

AC = BD (C.P.C.T)

HENCE PROVED

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