Question

Two triangles are having equal heights and their bases are 4cm and 9cm respectively .Then the ratio of areas of two triangles is......​

Answer 1

$Let \: the \: height \: of \: two \: triangles = h\:cm$

$base \: of \: the \: first \: triangle (b_{1}) = 4\:cm$

$base \: of \: the \: second \: triangle (b_{2}) = 9\:cm$

$\boxed { \blue {Area \:of \:a \: triangle = \frac{1}{2} \times (base )\times ( corresponding \:height )}}$

$\red{ Ratio \:of \:areas } = \frac{\frac{1}{2} \times b_{1} h }{\frac{1}{2} \times b_{2} h }\\= \frac{b_{1}}{b_{2}} \\= \frac{4\:cm }{9\:cm } \\= \frac{4}{9} \\= 4 : 9$

Therefore.,

$\red{ Ratio \:of \:areas\: of \:two \: triangles} \green { = 4 : 9 }$

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Answer 2

Step-by-step explanation:

Ratio = 4:9