Question

Two triangles QPR and QSR, right angled at P and S respectively are drawn on the same base QR and on the same side of QR. If PR and SQ intersect at T, prove that PT × TR = ST × TQ

Answer 1

Step-by-step explanation:

In triangles PTQ, and STR

<QPT = <RST (A)

<PTQ = <STR (Vertically opposite angles) (A)

So, the triangles PTQ and STR are similar.

PQ/SR = PT/TS = QT/RT

PT/TS = QT/RT

PT x RT = QT x TS

Hence proved.

Answer 2

Answer:

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