Question

Two triangles with equal bases have height in the ratio 3:2 find the ratio of its area

Answer 1

Answer:

2:3

Step-by-step explanation:

let the 2 heights be 2h and 3h

area of first triangle

=1/2 *b * h

=1/2 * b * 2h

=b * h (2 gets cancelled in numerator and denominator)

area of first triangle = bh = 2* (1/2bh)

area of second triangle

=1/2 *b * h

=1/2 * b * 3h

=3 * (1/2bh)

area of second triangle  = 3* (1/2bh)

area of first triangle:area of second triangle

=2* (1/2bh): 3* (1/2bh)

=2:3 (1/2bh is common and therefore is cancelled on both sides)