Physics, asked by hritikd9002, 1 year ago

Two trolleys of mass M and 3M are connected by a spring. They are compressed and released , they move off in opposite direction and come to rest after covering s1 and s2 respectively. If the frictional force acting between the trolley and surface is same in both cases then the ratio of s1 and s2 is

Answers

Answered by chuneeth07
76

Answer:

3:1

Explanation:

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m1=m

m2=3m

m1v1=m2v2

v1/v2=m2/m1=3/1 .......1

1/2.m1.v1^2=Fs1...........2

1/2.m2.v2^2=Fs2........3

2/3

v1^2/3v2^2=s1/s2

s1:s2=3:1

Answered by mvdharshan2006
9

Answer:

Two trolleys of mass M and 3M are connected by a spring. They are compressed and released , they move off in opposite direction and come to rest after covering s1 and s2 respectively. If the frictional force acting between the trolley and surface is same in both cases then the ratio of s1 and s2 is

Explanation:

answer is 3:1

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