Two trolleys of mass M and 3M are connected by a spring. They are compressed and released , they move off in opposite direction and come to rest after covering s1 and s2 respectively. If the frictional force acting between the trolley and surface is same in both cases then the ratio of s1 and s2 is
Answers
Answered by
76
Answer:
3:1
Explanation:
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m1=m
m2=3m
m1v1=m2v2
v1/v2=m2/m1=3/1 .......1
1/2.m1.v1^2=Fs1...........2
1/2.m2.v2^2=Fs2........3
2/3
v1^2/3v2^2=s1/s2
s1:s2=3:1
Answered by
9
Answer:
Two trolleys of mass M and 3M are connected by a spring. They are compressed and released , they move off in opposite direction and come to rest after covering s1 and s2 respectively. If the frictional force acting between the trolley and surface is same in both cases then the ratio of s1 and s2 is
Explanation:
answer is 3:1
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