Math, asked by DEBJITBAAG, 19 days ago

Two tubes A and B are attached to a tank. A tube can fill the tank in 40 minutes and B can empty the tank in 1 hour. If the A tube is opened first and the two tubes are opened separately at 1 hour intervals, how long it will take to completely fill the tank?​

Answers

Answered by sandhyaupadhyay775
0

5 hours 53 minutes

In first minute A fill 4 units of water

In first minute A fill 4 units of waterIn second minute B empty 3 units of water

In first minute A fill 4 units of waterIn second minute B empty 3 units of waterAfter two minutes tanks has 1 units of water.

In first minute A fill 4 units of waterIn second minute B empty 3 units of waterAfter two minutes tanks has 1 units of water.Note: Decrease the higher value i.e 4 from total capacity 180−4=176 units.

In first minute A fill 4 units of waterIn second minute B empty 3 units of waterAfter two minutes tanks has 1 units of water.Note: Decrease the higher value i.e 4 from total capacity 180−4=176 units.1 unit filled in 2 minutes

In first minute A fill 4 units of waterIn second minute B empty 3 units of waterAfter two minutes tanks has 1 units of water.Note: Decrease the higher value i.e 4 from total capacity 180−4=176 units.1 unit filled in 2 minutes176 units filled in 352 minutes

In first minute A fill 4 units of waterIn second minute B empty 3 units of waterAfter two minutes tanks has 1 units of water.Note: Decrease the higher value i.e 4 from total capacity 180−4=176 units.1 unit filled in 2 minutes176 units filled in 352 minutesNow in next minutes pipe A will fill 4 units. And tank is full so total time taken is 352+1=353

In first minute A fill 4 units of waterIn second minute B empty 3 units of waterAfter two minutes tanks has 1 units of water.Note: Decrease the higher value i.e 4 from total capacity 180−4=176 units.1 unit filled in 2 minutes176 units filled in 352 minutesNow in next minutes pipe A will fill 4 units. And tank is full so total time taken is 352+1=353minutes or 5 hour 53 minutes.

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