Question

two tugboats are towing a ship, each exerts a force of 6000N and the angle b/w The two ropes is 60°. calculate the resultant force on the ship.

Answer 1

f= √(6000^2 + 6000^2 + 2*6000*6000*cos60)
f=√(72000000+72000000*(1/2))
f=√(108000000)

f=10392(approx.)

Answer 2

Answer:

F = 10392.30 N

Explanation:

It is given that,

Force exerted by two tugboats, $F_1=F_2=6000\ N$

The angle between two ropes, $\theta=60^{\circ}$

Let F is the resultant force on the ship. The resultant of two vectors is given by :

$F=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos\theta}$

$F=\sqrt{6000^2+6000^2+2\times 6000\times 6000\ cos(60)}$

F = 10392.30 N

So, the resultant force on the ship is 10392.30 N. Hence, this ist he required solution.