Two tungsten bulb of power 50w and 60w work on 220v potential difference . If they are connected in parallel how much current will flow in the conductor ?
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Rujula16s:
it was the question in SSC boards
Answers
Answered by
6
P= Ixt
50+60 =220xt
110=220xt
T=220/110
Therefore t =2 ohms
Answered by
6
Hey dear,
● Answer -
I = 0.5 A
● Explanation -
# Given -
P1 = 50 W
P2 = 60 W
V = 220 V
# Solution -
For bulbs connected in parallel, equivalent power is given by -
P = P1 + P2
P = 50 + 60
P = 110 W
Power of bulbs combined is calculated by formula -
P = VI
I = P / V
I = 110 / 220
I = 0.5 A
Therefore, current passing through circuit is 0.5 A.
Hope this helps you...
● Answer -
I = 0.5 A
● Explanation -
# Given -
P1 = 50 W
P2 = 60 W
V = 220 V
# Solution -
For bulbs connected in parallel, equivalent power is given by -
P = P1 + P2
P = 50 + 60
P = 110 W
Power of bulbs combined is calculated by formula -
P = VI
I = P / V
I = 110 / 220
I = 0.5 A
Therefore, current passing through circuit is 0.5 A.
Hope this helps you...
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