Question

Two tungsten bulbs of wattage 100 W and 60 W power work on 220 V potential difference. if they are connected in parallel, how much current will flow in the main conductor
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Answer 1

Answer: 0.72A

Explanation : Power = V x I.

100 Watts = 100/220 =0.45 A

60 W = 0,27 A ,

0.45⁺0.27=0.72 A

Answer 2

Question :-

Two tungsten bulbs of wattage 100 W and 60 W power work on 220 V potential difference. if they are connected in parallel, how much current will flow in the main conductor?

Solution :-

Given data,

$P _{1}= 100 \: W , P _{2}= 60 \: W, V = 220 \: V$

To find,

$\: \: \: \: I = ?$

We know that,

$I = \frac{P}{V} \\ \\ ∴ P = VI$

Also,

$\: \: \: \: \: \: I_{1} = \frac{P _{1} }{V} \: \: And \: \: I _{2}= \frac{P _{2} }{V}$

$Current \: in \: the \: main \: conductor \: , \\ I = I _{1} + I _{2} \: \: ( \: Parallel \: connection \: ) \: \\ \\ = \frac{P _{1} }{V} + \frac{P_{2}}{V} = \frac{P_{1}+P_{2}}{V} = \frac{100W + 60 W }{220 V } = \frac{160}{220} A \\ \\ \underline{\bf {\underline{\ {=0.727 A [ \: Nearly \: 0.73 A \: ]}}}}$

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