Question

two tuning forks a and b produce 10 beats per second. on loading a small ring on one prong of b again 10 beats per second are produced. what was the frequency of b before loading small ring if now frequency of b is 430 hz? give reason

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Answer 1

Explanation:

Two tuning forks X and Y sounded together produce 10 beats per second. When Y is slightly loaded with wax, the number of beats reduces to 6 per second. If the frequency of X is 480 Hz, find that of Y.Read more on Sarthaks.com - https://www.sarthaks.com/624565/two-tuning-forks-and-sounded-together-produce-beats-per-second-when-slightly-loaded-With

Frequency of x = 480 Hz No. of beats with y = 10 ∴ Frequency of y = 480 +10 or 480-10 i.e., 490 or 470

On loading y, number of beats = 6 Frequency of y after loading = 486 or 474 ∴ The frequency of y before loading can not be 470, because if it were 470 before loading, it must be less than 470 after loading. ∴ Actual frequency of y = 490Hz