Two tuning forks give 6 beats per second when sounded together the frequency of one of the tuning forks is 480 hertz if first tuning fork is filed a little and then the number of Beats become 8 per second, find the frequency of second tuning fork
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with the wax the frequency of A is (480 +4) =484 Hz
without the wax the frequency of A is 486 Hz(480 +6)=486
since adding mass lowers the frequency we know that A was 484Hz instend ok 474 Hz because lowering the frequency of 478Hz would cause more beats to be heard
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Answer:474Hz
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