Two tuning Forks having frequencies 320 Hz
and 340 Hz ore Sounded together to produce
sound waves the velocity of sound in air
is 326.4 m/s Find the difference in
wavelength of these waves
Answers
Given:
1st Tuning Fork
Frequency (f1) = 320Hz
Velocity of sound in air (v) = 326.4m/s
2nd Tuning Fork
Frequency (f2) = 340Hz
Velocity of sound in air (v) = 326.4m/s
To find the difference in wavelength of the waves produced by them:
Solution:
Wavelength (λ1) of the 1st tuning fork is,
λ1 = v/f1
=326.4/320
λ1 = 0.98m
Wavelength (λ2) of the 2nd tuning fork is,
λ2 = v/f2
= 326.4/340
λ2=0.96m
Difference of these wavelengths = λ1-λ2 =0.98-0.96 =0.02m
So, the difference in wavelength of these waves is 0.02m.
Answer:
Concept:
The length of a complete wave cycle is measured in wavelength. A wave's velocity is the distance traveled by a point on the wave. In general, the relationship between Velocity and Wavelength is proportional for any wave.
Explanation:
wavelength and Velocity
The velocity of a wave is given by the product of its wavelength and frequency. It is given mathematically by the wave velocity formula, which is written as
Where,
V is the velocity of the wave measured in meters per second.
f is the frequency of the wave measured in hertz.
is the wavelength of the wave measured in millimeters.
To determine the wavelength difference between the waves produced by them:
Solution:
The first tuning fork's wavelength is,
= v/f1
=326.4/320
= 0.98m
The second tuning fork's wavelength is,
= v/f2
= 326.4/340
=0.96m
The difference between these wavelengths =0.98 – 0.96 = 0.02m
So the wavelength difference between these waves is 0.02m.
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