Question

Two tuning forks of frequencies 320 Hz and 340
Hz respectively produce sound waves in air. If their
wavelengths different by 6 cm, the velocity of
sound in air is :​

Answer 1

Step-by-step explanation:

Two tuning forks of frequencies 320 Hz and 340 Hz respectively produce sound waves in air. If their  wavelengths different by 6 cm, the velocity of  sound in air is :

• Now frequency n1 = 320 hz and n2 = 340 hz
• We need to find the velocity of sound in air.
• Also given λ1 – λ2 = 6 cm
•          Now v/n1 – v/n2 = 6 x 10^-2 m
•          So v (1/n1 – 1/n2) = 6 x 10^-2
•           So v (1/320 – 1/340) = 6 x 10^-2
•             Or v (17 – 16 / 5440) = 6 x 10^-2
•               Or v = 5440 x 6 x 10^-2
•             Or v = 326.4 m / s
• The velocity of  sound in air is 326.4 m/s

Reference link will be

https://brainly.in/question/8627045