Two tuning forks of frequency 520 Hz and 524 Hz are vibrated together. The time interval between successive maximum and minimum intensities is
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Answered by
59
Hello Dear.
Here is the answer---
→→→→→→→→
f₁ = 520 Hz.
f₂ = 524 Hz.
Time Interval = 1/(f₂ - f₁)
= 1(524 - 520)
= 1/4 seconds.
Thus, Time Interval Between the Maximum and Minimum Intensities is 0.25 seconds.
→→→→→→→→→
Hope it helps.
Here is the answer---
→→→→→→→→
f₁ = 520 Hz.
f₂ = 524 Hz.
Time Interval = 1/(f₂ - f₁)
= 1(524 - 520)
= 1/4 seconds.
Thus, Time Interval Between the Maximum and Minimum Intensities is 0.25 seconds.
→→→→→→→→→
Hope it helps.
Answered by
63
Two tunnig fork of frequency 520 Hz and 524Hz are vibrated together. It means beats form due to it .
f₁ = 524 Hz
f₂ = 520 Hz
Beat period = 1/number of Bea are formed per unit time
= 1/(f₁ - f₂)
= 1/(524 - 520)
= 1/4 sec
Now, time inveral between successive maximum and minimum intensities = beat period= 1/4 sec
f₁ = 524 Hz
f₂ = 520 Hz
Beat period = 1/number of Bea are formed per unit time
= 1/(f₁ - f₂)
= 1/(524 - 520)
= 1/4 sec
Now, time inveral between successive maximum and minimum intensities = beat period= 1/4 sec
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