Biology, asked by chandranshekhar205, 1 year ago

Two tuning forks of frequency 520 Hz and 524 Hz are vibrated together. The time interval between successive maximum and minimum intensities is

Answers

Answered by tiwaavi
59
Hello Dear.

Here is the answer---

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f₁ = 520 Hz.
f₂ = 524 Hz.

Time Interval = 1/(f₂ - f₁)
                      = 1(524 - 520)
                      = 1/4 seconds.

Thus, Time Interval Between the Maximum and Minimum Intensities is 0.25 seconds.

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Hope it helps.
Answered by abhi178
63
Two tunnig fork of frequency 520 Hz and 524Hz are vibrated together. It means beats form due to it .
f₁ = 524 Hz
f₂ = 520 Hz
Beat period = 1/number of Bea are formed per unit time
= 1/(f₁ - f₂)
= 1/(524 - 520)
= 1/4 sec

Now, time inveral between successive maximum and minimum intensities = beat period= 1/4 sec
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