Question

Two tuning forks 'P' and 'Q' when sounded together produce 10 beats
per second. On loading fork 'P' with a little wax, when sounded
together, forks 'P' and 'Q' produce 4 beats per second. If the frequency
of fork 'Q' is 620 Hz., determine the frequency of fork P.

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Answer 1

Answer:

Frequency of tuning fork P is 630 Hz

Explanation:

As we know that the beat frequency is the difference of two frequency which sounded together

So we will have

$f_a - f_b = 10$

Or

$f_b - f_a = 10$

now we added wax on P due to which the beat frequency is reduced and it becomes 4

so here correct relation must be

$f_a - f_b = 10$

as we know

$f_b = 620 Hz$

so we have

$f_a = 620 + 10$

$f_a = 630 Hz$

#Learn

Topic : Beats

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