Question

Two tuning forks 'P' and 'Q' when sounded together produce 10 beatsper second. On loading fork 'P' with a little wax, when soundedtogether, forks 'P' and 'Q' produce 4 beats per second. If the frequencyof fork 'Q' is 620 Hz., determine the frequency of fork P.​

Answer 1

Answer:

Frequency of tuning fork P is 630 Hz

Explanation:

As we know that the beat frequency is the difference of two frequency of two sources

So it is given as either

$f_p - f_q = 10$

Or

$f_q - f_p = 10$

Now little wax is applied on P so that the frequency of P is decreased

Now beat frequency is also decreased to 4 beats per sec

So the correct relation must be

$f_p - f_q = 10$

given that

$f_q = 620 Hz$

so we have

$f_p = 630 Hz$

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Topic : Beats Effect

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