Question

Two tuning forks 'P' and 'Q' when sounded together produce 10 beatsper second. On loading fork 'P' with a little wax, when soundedtogether, forks 'P' and 'Q' produce 4 beats per second. If the frequencyof fork 'Q' is 620 Hz., determine the frequency of fork P.​

Answer 1

Frequency of fork P is 630 Hz .

Given :

Frequency of fork Q , 620 Hz .

Initial beats , 10 .

Beats after loading fork P , 4 .

Now , after loading ( it will decrease frequency of fork ) the beats will decrease .

Therefore , frequency of fork P is greater than Q .

So, beat is difference between the frequency of forks.

$10=f_P-f_Q\\\\10=f_P-620\\\\f_P=630\ Hz$

Hence , this is the required solution.

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