Physics, asked by vedika2k1, 7 months ago

Two tuning forks when sounded together produce 3 beats per second. On loading one of these forks with wax and again sounding them together, 20 beats are heard in 4
seconds. Calculate the frequency of the loaded tuning fork if the frequency of the other fork is 386hz. Explain

Answers

Answered by Anurag2099
0

Answer:

252

Explanation:

Since four beats per second are heard when A and B are sounded together, 256Hz−ν=±4Hz

where ν is the frequency of B.

Now, loading with wax decreases the frequency of tuning fork.

Waxing tuning fork A would mean the frequency of A has reduced such a way that it again produces 4 beats per second with B. Thus it is now lower than B by 4Hz and initially it was higher than B by 4Hz.

⟹256Hz−ν=4Hz

⟹ν=252Hz

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