Math, asked by BurningGem, 1 month ago

two two digit numbers are written one after the other to give four digit number such that the larger two digit number is written first. now the difference of four digit number and the sum of a two digit number is 5742 then the larger two digit number is .please answer properly

its from the chapter pair of linear equations in two variables​

Answers

Answered by SidMistry
0

Answer:

Step-by-step explanation:

5812 - (58 + 12) = 5742

5812 - 70 = 5742

The digits are 58 and 12

Note: Just thinking through and getting the clue would help solve this kind of problem.

Answered by Anonymous
2

Answer:

Let the 1st, 2nd, 3rd and 4th digits be a,b,c and d respectively.

So, four-digit no. will be dcba

→   According to the given question,

⇒  a+b=c+d        --- ( 1 )

⇒  a+d=c            --- ( 2 )

⇒  b+d=2(a+c)     ---- ( 3 )

∴   a+b=a+2d         [ Substituting value of equation ( 2 ) in equation ( 1 ) ]

∴   b=2d    --- ( 4 )

⇒  2d+d=2(a+a+d)        [ Substituting eq ( 4 ) and ( 2 ) in eq. ( 3 ) ]

∴   d=4a or a=4d      --- ( 5 )

⇒  4d+d=c   ---  [Substituting ( 5 ) in ( 2 ) ]

∴   c=45d or c=4d5

Now d=4a

Since a and d are single digits and we have to form 4 digit no. a<10 and 0<d<10

So, the possible integer values of a and d which satisfy d=4a are

1.a=1,d=4

2.a=2,d=8

∴   The value of d can be either 4 or 8

⇒  When d=4, then c=5.

⇒  When d=8, then 

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