Question

Two types of oil A and B have been mixed in the ratio of 3 : 2 and total mixture is 90 litre. When 1 by 3rd of mixture was consumed some more quantity of oil A was mixed with the mixture and the
ratio was made as 2: 1. Find out how much quantity of A was mixed lateron.
IAns.12litrell

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Answer 1

Given :

A : B = 3 : 2

Total mixture = 90L

1/3 of mixture was consumed

After adding some amount of oil A with the mixture the ratio become 2:1

To find :

How much quantity of A was added to the mixture

Solution :

Quantity of A in the mixture = $\frac{3}{3+2 }*90$ = $\frac{3}{5} *90$ = 3 × 18 = 54L

Quantity of A in the mixture = $\frac{2}{3+2}*90 = \frac{2}{5}*90$ = 2 × 18 = 36L

1/3rd of mixture was consumed.

So, A consumed = $54*\frac{1}{3}$ = 18L

A remained = 54 - 18 = 36L

B consumed = $36*\frac{1}{3}$ = 12L

B remained = 36 -12 = 24L

Let x be the oil added

$\frac{(36 + x )/(36+x+24) }{24/(36+x+24)} = \frac{2}{1}$

$\frac{36+x}{24} = \frac{2}{1}$

36 + x = 48

x = 48 - 36

x = 12L

So, 12L of oil A was mixed with the mixture

Answer 2

Step-by-step explanation:

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