Question

Two types of tea are mixed in the ratio 3:5 to make first quality and in the ratio 2:3 to make second quality. how many kilograms of first quality has to be mixed with 10 kg of the second quality so that the third quality having the two varieties in the ratio of 8:11 may be produced? 1)5 kg2)10 kg3)8 kg4)none of these

Answer 1

8 kg is required so that 3 ed quality produced

Answer 2

Answer:

Option D - None of these

Step-by-step explanation:

Given : Two types of tea are mixed in the ratio 3:5 to make first quality and in the ratio 2:3 to make second quality.

To find : How many kilograms of first quality has to be mixed with 10 kg of the second quality so that the third quality having the two varieties in the ratio of 8:11 may be produced?

Solution :

Let the common ration of the first quality oil be x.

The ratio given is 3:5

So, the total quantity of the first quality oil = 3x+5x=8x

The total quantity of the second quality oil = 10 kg

The ratio given is 2:3

So, the quantity of first oil variety $= (\frac{2}{5})\times10 = 4kg$

The quantity of second oil variety $=(\frac{3}{5})\times10 = 6kg$

The third ratio is got by mixing the first quality and 10 kg of second quality.

The ratio given is 8:11

So, $\frac{3x+4}{5x+6}=\frac{8}{11}$

$11(3x+4)=8(5x+6)$

$33x+44=40x+48$

$33x-40x=48-44$

$-7x=4$

$x=-\frac{4}{7}$

Which is not possible as quantity cannot be negative.

Therefore, Option D is correct - None of these.