Math, asked by AryanSuperKid5828, 10 months ago

Two unbaised dice are thrown .find the probability that sum of the faces is not less than 10

Answers

Answered by AaronNoronha
0

Answer: 1/6

Step-by-step explanation:

Two dice are thrown, so possible outcomes are :  

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Sum of faces not less than 10 are (4,6), (5,5), (5,6), (6,4), (6,5), (6,6)

Therefore 6 possibilities

P(sum of the faces is not less than 10) = 6/36

                                                               = 1/6

Therefore the probability that sum of the faces is not less than 10 is 1/6

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