Two unbiased coins are tossed. If one coin shows head, the probability that the other also shows head is...,Select Proper option from the given options.
(a) 1/4
(b) 1/2
(c) 1/8
(d) 1
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This is a contradicting question. You know that coins are unbiased , but if one coin is tossed after the other , it becomes a biased situation. Anyway if the situation, is unbiased, the probability of getting a heads is 50%. If the situation is biased and one of the coin shows head , the probability of the other coin being heads would reduce and become 1/4.
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Two unbiased coins are tossed...
so, sample space, S = {(T,T), (T,H) ,(H,T) , (H, H)}
number of sample space, n(S) = 4
favourable outcomes , n(E) = 1 [ because other coin also shows Head has only one possibility e.g., (H, H)]
now, probability that other coin also shows head , P(E) = n(E)/n(S) = 1/4
hence, option (a) is correct.
so, sample space, S = {(T,T), (T,H) ,(H,T) , (H, H)}
number of sample space, n(S) = 4
favourable outcomes , n(E) = 1 [ because other coin also shows Head has only one possibility e.g., (H, H)]
now, probability that other coin also shows head , P(E) = n(E)/n(S) = 1/4
hence, option (a) is correct.
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