Two unbiased coins are tossed simultaneously. find the probability of getting:
a.two heads
b.one head
c.at least one head
d.at most one head
e.no head
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Back to basics - there are 3 possible (mutually exclusive) outcomes 2H,0T; 1H,1T; 0H,2T. That means that the sum of the 3 probabilities add to 1. The probabilities can be calculated using the binomial distribution. The question asks for P{2H,0T} + P{1H,1T} which is not too hard to calculate, but laziness is a virtue!
Here’s the lazy way P{2H,0T} + P{1H,1T} = 1 - P{0H,2T} and so we can get the answer calculating only one binomial probability and doing the subtraction.
The probability of getting 2T is easy to calculate even mentally - so that, and the subtraction from 1 are left for the reader
Here’s the lazy way P{2H,0T} + P{1H,1T} = 1 - P{0H,2T} and so we can get the answer calculating only one binomial probability and doing the subtraction.
The probability of getting 2T is easy to calculate even mentally - so that, and the subtraction from 1 are left for the reader
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