Question

Two unbiased coins are tossed simultaneously, then the probability of getting no head is
of(x+y)*2

Answer 1

Answer:

Given :- Two unbiased coins are tossed simultaneously, then the probability of getting no head is p/q. Find the value of (p + q)2 ?

Solution :-

we know that,

Probability (P) = Favourable number of cases / Total number of cases .

If two unbiased coins are tossed simultaneously, then the total number of possible outcomes may be = HH, HT , TH or TT .

So, here total number of possible cases = 4 .

Now, favourable outcomes for no head means both are tails.

→ No. of favourable outcomes = TT = 1

→ Total number of possible cases = 4

As we know that,

→ Probability (P) = Favourable number of cases / Total number of cases

therefore,

→ Probability of no head = 1/4 .

hence,

→ 1/4 = p/q

p = 1

q = 4

so,

→ (p + q)2

→ (1 + 4) * 2

→ 5 * 2

→ 10 (Ans.)

or,

→ (p + q)²

→ (1 + 4)²

→ 5²

→ 25 . (Ans.)

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