Question

two unbiased dice ar rolled. find the probability that the sum of the numbers on the two faces is either divisible by 5 or divisible by 6​

Answer 1

Answer:

Possible outcomes 6^2=36

multiple of 5=5,10,15,20,25,30,35,40,45...

multiple of 6=6,12,18,24,30,36,...

See the table now...

so total wanted outcomes=12

Probability=12÷36=1/3

Answer 2

Step-by-step explanation:

here

total number n(s) = 36

divisible by 5 n(A) = 7

divisible by 5 n(B) = 6

Now,

p( AorB) =p(AuB) = n(A)/n(s) + n(AB/n(s)

= 7/36+6/36

=13/36

so, p(AuB)=13/36