Two unbiased dice are rolled once.what is the probability of getting (1) a doublet
(2) a sum equal to 7
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Step-by-step explanation:
total outcomes are 1,1;1,2-----------6,6 that are 36 in number
(1) favourable outcome for doublets are 1,1 2,2 3,3 ------6,6 that are 6 in number so
p(doublet)=6/36=1/6
(2) favourable outcome for sum =7 are 1,6 ;2,5 ;3,4; 4,3 ;5,2 ;6,1 that are 6 in number so
p(sum =7)=6/36=1/6
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