Math, asked by davinder234, 1 year ago

Two unequal angles of a parallelogram are in the ratio 2:3. FIND ALL ITS ANGLES IN DEGREES


aishowrya: hey here is the
aishowrya: Solution:

Let ABCD be a parallelogram 



Then, AD ∥ BC and AB is a transversal. 

Therefore, A + B = 180° [Since, sum of the interior angles on the same side of the transversal is 180°] 

Similarly, ∠B + ∠C = 180°, ∠C + ∠D = 180° and ∠D + ∠A = 180°. 

Thus, the sum of any two adjacent angles of a parallelogram is 180°. 

Hence, any two adjacent angles of a parallelogram are supplementary. 

Answers

Answered by ayushisrivastava986
241
Ratio of the 2 angles :- 2:3
Angle 1 -2x
Angle 2 - 3x
THE OPPOSITE ANGLES OF A PARALLELOGRAM ARE EQUAL SO:-
2x +3x + 2x + 3x = 360
10x = 360
x = 360/10
x = 36
2x = 72
3x = 108

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Answered by muscardinus
20

Given that,

Two unequal angles of a parallelogram are in the ratio 2:3.

To find,

All its angles in degrees.

Solution,

Let angle A is 2x and angle B is 3x

We know that the sum of co-interior angles are supplementary.

So,

\angle A+\angle B=180^{\circ}\\\\2x+3x=180\\\\5x=180\\\\x=36^{\circ}

It means that, \angle A=2x=2(36)=72^{\circ}

and

\angle B=3x=3(36)=108^{\circ}

Also, the opposite angles of a parallogram are equal

So,

\angle A=\angle C=72^{\circ}\\\\\angle B=\angle D = 108^{\circ}

Hence, this is the required solution.

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