Two unequal circles with centres A and
B intersect each other at points C and
D. The centre B of the smaller circle lies
on the circumference of the bigger circle
with centre A. If angle CMD = x, find in
terms of x. the measure of angle DAC.
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Answer:
angle DAC= 360-4X
Step-by-step explanation:
angle CBN and angle BDN are tangents to circle with centre o therefore,both the angles are 90 degree.
now,since we know that the angle subtended at the centre is double the angle subtended by the chord then,angle CBD is 2X
we even know that the sum of angles of a quadrilateral is 360 then,90+90+2X+Angle CND=360
angle CND is half angle CAD then
180+1/2 angle CAD +2X=360
CAD= 360-4X.
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